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The current in a hair dryer measures 15 amps the resistance of the hair dryer is 8 ohms

Respuesta :

AL2006

The voltage at the input to the hair dryer is

V = (current) · (resistance)

V = (15 A) · (8 Ω)

V = 120 volts

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The power dissipated by the hair dryer is

P = (current)²· (resistance)

P = (15 A)² · (8 Ω)

P = 1800 watts

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