Answer:
0.712 mH
Explanation:
The emf produced by the coil = 2.6 V
Current is changes from -29 mA to 33 mA so change in current di =33-(-29)=62 mA
The time duration that is dt=17 ms
The emf is given by [tex]e=L\frac{di}{dt}[/tex]
[tex]2.6=L\frac{62}{17\times 10^{-3}}[/tex]
[tex]L=0.712\times 10^{-3}H=0.712mH[/tex]
So the value of inductance will be 0.712 mH
