Answer:
No. of 100 W bulbs, n = 28,539 bulbs
Given:
Power of a single bulb = 100 W
Time period, T = 1 yr = [tex]365\times 24\times 60\times 60[/tex] = 31,536,000 s
mass of matter, m = 1 g = [tex]1\times 10^{-3}][/tex]
Solution:
According to Eintein's mass-energy equivalence:
E = [tex]mc^{2}[/tex]
E = [tex]1\times 10^{-3}\times (3\times 10^{8})^{2}[/tex]
E = [tex]9\times 10^{13} J[/tex]
Power of a single bulb, P = [tex]\frac{E}{T}[/tex]
P = [tex]\frac{9\times 10^{13} }{31,536,000}[/tex]
P = 28,53,881 W
No. of 100 W bulbs, n = [tex]\frac{P}{power of one bulb}[/tex]
n = [tex]\frac{28,53,881}{100}[/tex]
n = 28,539
