Explanation:
It is given that,
Object distance from a concave mirror, u = -33 cm
Radius of curvature of the mirror, R = -24 cm (in front of mirror)
(a) The relation between focal length (f) of the mirror and the radius of curvature is given by :
R = 2 × f
[tex]f=\dfrac{R}{2}[/tex]
f = -12 cm
(b) Mirror's formula is given by :
[tex]\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}[/tex], v is the image distance
[tex]\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}[/tex]
[tex]\dfrac{1}{v}=\dfrac{1}{-12}-\dfrac{1}{-33}[/tex]
v = −18.85 cm
(c) The image formed by a concave mirror is real and inverted. Magnification of the mirror is given by :
[tex]m=\dfrac{-v}{u}[/tex]
[tex]m=\dfrac{-(-18.85)}{-33}[/tex]
m = -0.57
As the magnification of the mirror is less than 1, so the image is inverted. Hence, this is the required solution.