Answer:
Launch velocity of the balloon is 40.23 m/s.
Explanation:
It is given that,
Height above ground, h = 75 m
Velocity of balloon on its upward trajectory, u = 12.2 m/s
We need to find the launch velocity of the balloon. Let it is equal to v. Applying the conservation of energy as :
[tex]mhg+\dfrac{1}{2}mu^2=\dfrac{1}{2}mv^2[/tex]
[tex]hg+\dfrac{1}{2}u^2=\dfrac{1}{2}v^2[/tex]
[tex]75(9.8)+\dfrac{1}{2}(12.2)^2=\dfrac{1}{2}v^2[/tex]
[tex]v=40.23\ m/s[/tex]
So, the launch velocity of the balloon is 40.23 m/s. Hence, this is the required solution.
