Answer:
[tex]EMF_{max} = 2.26 Volts[/tex]
Explanation:
As we know that the rotating coil will have change in the angle with time at all instant of time
so at any general instant of time we can say
[tex]\phi = NBA cos\omega t[/tex]
now we have
[tex]EMF = \frac{d\phi}{dt}[/tex]
so we have
[tex]EMF = NBA\omega sin\omega t[/tex]
so we have maximum induced EMF in the coil is given as
[tex]EMF_{max} = NBA\omega[/tex]
[tex]EMF_{max} = (2\pi f)NBA[/tex]
N = 904 turns
B = 0.001 T
[tex]A = 61.163 cm^2 = 61.163 \times 10^{-4} m^2[/tex]
f = 65 Hz
now we have
[tex]EMF_{max} = (904)(0.001)(61.163 \times 10^{-4})(2\pi\times 65)[/tex]
[tex]EMF_{max} = 2.26 Volts[/tex]
