Answer:
Head loss in 100 m length equals 1.00 m.
Explanation:
The head loss in an open channel is calculated using manning's equation as follows
[tex]Q=\frac{1}{n}\frac{A^{5/3}}{P^{2/3}}S_{f}^{1/2}[/tex]
For a asphalt rectangular channel we have
Area of flow = [tex]3.0\times 2.0 = 6m^{2}[/tex]
Wetted Perimeter = [tex]3.0+2\times 2.0=7.0m[/tex]
manning's roughness coefficient = 0.016
Applying values in the above equation we get
[tex]33.84=\frac{1}{0.016}\times \frac{6^{5/3}}{7^{2/3}}S_{f}^{1/2}\\\\\therefore S^{1/2}_{f}=0.1\\\\\therefore S_{f}=0.01[/tex]
Now we know that
[tex]S_{f}=\frac{H_{L}}{L}\\\\\therefore H_{l}=0.01\times 100m=1.00m[/tex]
