Explanation:
It is given that,
Capacitance, [tex]C=5\ \mu F=5\times 10^{-6}\ F[/tex]
Voltage, V = 500 volts
Charge on the plates, [tex]Q=C\times V[/tex]
[tex]Q=5\times 10^{-6}\ F\times 500[/tex]
Q = 0.0025 C
Energy stored in the capacitor is given by :
[tex]E=\dfrac{1}{2}CV^2[/tex]
[tex]E=\dfrac{1}{2}\times 5\times 10^{-6}\ F\times (500\ V)^2[/tex]
E = 0.625 Joules
Hence, this is the required solution.
