Explanation:
Antoine equation is as follows.
[tex]log_{10} P = A - \frac{B}{C + T}[/tex]
It water is at [tex]75^{o}C[/tex], then values of constants A, B, and C will be as follows.
A = 8.07131, B = 1730.63, C = 233.426
When pressure, P = 2.5 atm then putting these given values into the above equation as follows.
[tex]log_{10} P = A - \frac{B}{C + T}[/tex]
[tex]log_{10} (2.5 \times 101.325 \times 10^{3}) = (8.07131 - \frac{1730.63}{233.426 + T})[/tex]
5.40365 = [tex]8.07131 - \frac{1730.63}{233.4 + T}[/tex]
T = [tex]415.33^{o}C[/tex]
Converting the temperature into Fahrenheit as follows.
[tex]T_{F}[/tex] = [tex]\frac{9}{5} \times 415.33 + 32[/tex]
= [tex]779.5^{o}F[/tex]
Thus, we can conclude that the boiling temperature of the water is [tex]779.5^{o}F[/tex].