Answer:
Heat dissipated, H = 1440 Joules
Explanation:
It is given that,
Resistor 1, [tex]R_1=30\ ohms[/tex]
Resistor 2, [tex]R_2=20\ ohms[/tex]
Voltage, V = 10 volts
Both resistors are connected in series. The equivalent resistance is given by :
[tex]R=R_1+R_2[/tex]
R = 30 + 20
R = 50 ohms
In series combination, the current throughout the circuit remains the same. It can be calculated using ohm's law as :
V = IR
[tex]I=\dfrac{V}{R}[/tex]
[tex]I=\dfrac{10}{50}[/tex]
I = 0.2 A
Heat dissipated in R2 during (1/2) h, t = 1800 s is given by :
[tex]H=I^2R_2 t[/tex]
[tex]H=(0. 2)^2\times 20\times 1800[/tex]
H = 1440 J
So, the heat dissipated during 1800 seconds is 1440 Joules. Hence, this is the required solution.
