Two small metal spheres are 25 cm apaft.The spheres have equal amount of negative charge and repel each other with a force of 0.036 N. What is the magnitude of the charge on each sphere? (a) 2x10-3 C (h) 3 x 10-4C

Respuesta :

Answer:

[tex]0.5\times 10^{-6}C[/tex]

Explanation:

According to coulombs law force between two charges is given by [tex]F=\frac{1}{4\pi \epsilon _0}\frac{Q_1Q_2}{R^2}[/tex] here R is the distance between both the charges which is given as 25 cm

We have given force F =0.036 N

So  [tex]0.036=\frac{1}{4\pi \times 8.85\times 10^{-12}}\frac{Q^2}{(0.25^2)}[/tex] As [tex]\epsilon _0[/tex] is constant which value is [tex]8.85\times 10^{-12}[/tex]

[tex]Q^2=0.250\times 10^{-12}[/tex]

[tex]Q=0.5\times 10^{-6}C[/tex]