Explanation:
It is given that,
Force acting on the student, F = 560 N
Vertical height, h = 2.7 m
Time taken, t = 27 s
(a) Work done, W = F × h
[tex]W=560\ N\times 2.7\ m[/tex]
W = 1512 Joules
(b) The power output of the student is given by :
[tex]P=\dfrac{W}{t}[/tex]
[tex]P=\dfrac{1512\ J}{2.7\ s}[/tex]
P = 560 watts
Hence, this is the required solution.
