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A certain freely falling object, released from rest, requires 1.60 s to travel the last 29.0 m before it hits the ground. (a) Find the velocity of the object when it is 29.0 m above the ground. (Indicate the direction with the sign of your answer. Let the positive direction be upward.)

Respuesta :

Answer:

-10.277 m/s

Explanation:

t = Time taken = 1.6 s

s = Distance travelled = 29 m

u = Initial velocity

a = Acceleration due to gravity = 9.81 m/s²

[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow -29=u\times 1.6-\frac{1}{2}9.81\times 1.6^2\\\Rightarrow -29+\frac{1}{2}9.81\times 1.6^2=u1.6\\\Rightarrow -16.4432=u1.6\\\Rightarro u=\frac{-16.4432}{1.6}=-10.277\ m/s[/tex]

∴ Velocity of the object when it is 29.0 m above the ground is -10.277 m/s

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