Respuesta :
Answer:
Head loss = 28.03 m
Explanation:
According to Bernoulli's theorem for fluids we have
[tex]\frac{P}{\gamma _{w}}+\frac{V^{2}}{2g}+z=Constant[/tex]
Applying this between the 2 given points we have
[tex]\frac{P_{1}}{\gamma _{w}}+\frac{V_{1}^{2}}{2g}+z_{1}=\frac{P_{2}}{\gamma _{w}}+\frac{V_{2}^{2}}{2g}+z_{2}+h_{l}[/tex]
Here [tex]h_{l}[/tex] is the head loss that occurs
[tex]\therefore h_{l}=\frac{P_{1}}{\gamma _{w}}+\frac{V_{1}^{2}}{2g}+z_{1}-\frac{P_{2}}{\gamma _{w}}-\frac{V_{2}^{2}}{2g}-z_{2}[/tex]
Since the pipe is horizantal we have [tex]z_{1}-z_{2}=0[/tex]
Applying contunity equation between the 2 sections we get
[tex]A_{1}V_{1}=A_{2}V_{2}\\\\\therefore V_{1}=V_{2}(\because A_{1}=A_{2})[/tex]
Since the cross sectional area of the both the sections is same thus the speed
is also same
Using this information in the above equation of head loss we obtain
[tex]h_{l}=\frac{1}{\gamma _{w}}(P_{1}-P_{2})[/tex]
Applying values we get
[tex]h_{l}=\frac{1}{9810}\times (275\times 10^{3})m\\\\\therefore h_{l}=28.03m[/tex]
