Answer:
K.E = 0.0075 J
Explanation:
Given data:
Mass of the ball = 1.5 kg
radius, r = 50 cm = 0.5 m
Angular speed, ω = 12 rev/min = (12/60) rev/sec = 0.2 rev/sec
Now,
the kinetic energy is given as:
K.E = [tex]K.E=\frac{1}{2}I\omega^2[/tex]
where,
I is the moment of inertia = mr²
on substituting the values, we get
[tex]K.E=\frac{1}{2}\times1.5\times0.5^2\times0.2^2[/tex]
or
K.E = 0.0075 J
