Answer:
The point is rising at a speed of 27 m/s.
Step-by-step explanation:
The rim is represented in the figure that is attached
The tangential speed of the point on the rim is given by
[tex]V_{t}=\omega r[/tex]
Applying values we get
[tex]V_{t}=18rad/sec\times 3=54m/s[/tex]
Resolving the speed along the x and y axis as shown in the figure we get
[tex]V_{y}=V_{t}cos(\theta )\\\\\therefore V_{y}=54cos(\frac{\pi }{3})\\\\V_{y}=27m/s[/tex]
