Explanation :
It is given that,
Diameter of the coil, d = 20 cm = 0.2 m
Radius of the coil, r = 0.1 m
Number of turns, N = 3000
Induced EMF, [tex]\epsilon=1.5\ V[/tex]
Magnitude of Earth's field, [tex]B=10^{-4}\ T[/tex]
We need to find the angular frequency with which it is rotated. The induced emf due to rotation is given by :
[tex]\epsilon=NBA\omega[/tex]
[tex]\omega=\dfrac{\epsilon}{NBA}[/tex]
[tex]\omega=\dfrac{1.5}{3000\times 10^{-4}\times \pi (0.1)^2}[/tex]
[tex]\omega=159.15\ rad/s[/tex]
So, the angular frequency with which the loop is rotated is 159.15 rad/s. Hence, this is the required solution.
