If you want to construct an LC circuit that resonates at 0.9 MHz, what should the inductor be if the capacitor is 3.1 pF ?

Respuesta :

Answer:

[tex]L=0.0101\times 10^{-6}H[/tex]

Explanation:

We have given resonates frequency f=0.9 MHz[tex]=0.9\times 10^9Hz[/tex]

The capacitance of the capacitor C =3.1 pF[tex]=3.1\times 10^{-12}F[/tex]

For an LC circuit resonance frequency is given by [tex]f=\frac{1}{2\pi \sqrt{LC}}[/tex]

[tex]0.9\times 10^9=\frac{1}{2\times 3.14\sqrt{3.1\times 10^{-12}L}}[/tex]

[tex]0.81\times 10^{18}=\frac{1}{4\times 9.8596\times 3.1\times 10^{-12}L}[/tex]

[tex]L=0.0101\times 10^{-6}H[/tex]