Respuesta :
9x^3-6x^2+3x
Basically with this you just wanna simplify each term one-by-one.
For instance, look at the first term, 27x^4
Imagine 27x^4/3x
3 goes into 27 9 times, and x goes into x^4 4 times (cuz x to the power of 4 is just x times x times x times x)
So you’re left with 9x^3
Answer:
[tex]9x^3-6x^2+3x[/tex]
Step-by-step explanation:
We have the following:
[tex]\frac{27x^4-18x^3+9x^2}{3x}[/tex]
which can be separeted like this:
[tex]\frac{27x^4}{3x} -\frac{18x^3}{3x} +\frac{9x^2}{3x}[/tex]
and using the rule:
[tex]\frac{x^m}{x^n}=x^{m-n}[/tex]
in other words we substract the exponents at the moment we make the division, and also dividing the coefficients ([tex]\frac{27}{3} =9,\frac{18}{3} =6, \frac{9}{3} =3[/tex]) we get the following:
[tex]9x^{4-1}-6x^{3-1}+3x^{2-1}\\=9x^3-6x^2+3x[/tex]
the answer is: [tex]9x^3-6x^2+3x[/tex]
