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A coin with diameter 2.00 cm is placed horizontally in water at a depth of 20.0 cm. The refractive index of water is 1.33 Find the apparent position and size of the image of the coin when viewed at normal incidence from a point above the surface.

Respuesta :

Answer:

apparent position = 26.6 cm

and size is same of coin because we observe it directly above of the coin

Explanation:

given data

diameter = 2 cm

depth = 20 cm

refractive index of water = 1.33

to find out

apparent position and size

solution

we know refractive index of air is 1

so apparent position of coin formula is

apparent position = [tex]\frac{refractive index of water}{refractive index of air} (depth)[/tex]       ..........................1

put here value in equation 1

apparent position = [tex]\frac{1.33}{1} (20)[/tex]

apparent position = 26.6 cm

and size is same of coin because we observe it directly above of the coin

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