Given a heat source of 200C and a heat sink of 20C, what is the maximum theoretical efficiency for a Carnot engine? (numerical percentage out of 100 without the % symbol)

Respuesta :

Answer : The maximum theoretical efficiency for a Carnot engine is 90.

Explanation :

Efficiency of carnot heat engine : It is the ratio of work done by the system to the system to the amount of heat transferred to the system at the higher temperature.

Formula used :

[tex]\eta \%=\frac{Q_h-Q_c}{Q_h}\times 100[/tex]

where,

[tex]\eta[/tex] = efficiency of carnot engine = ?

[tex]Q_h[/tex] = heat supplied by hot source = 200 C

[tex]Q_c[/tex] = heat supplied by cold source  = 20 C

Now put all the given values in this formula, we get :

[tex]\eta \%=\frac{Q_h-Q_c}{Q_h}\times 100[/tex]

[tex]\eta \%=\frac{200-20}{200}\times 100[/tex]

[tex]\eta \%=90[/tex]

Therefore, the maximum theoretical efficiency for a Carnot engine is 90.

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