Respuesta :
Explanation:
here u = 50m/s
v = 60m/s
t = 58 s
then a = (60-50)/58 m/s2
= 0.17m/s2
now s= ut+1/2at2
so , 50×58+0.5×0.17×(58)^2 m
= 3185.94 m
= 3.18 km
Answer:
The displacement of 3190 m a car can travel if velocity is accelerated uniformly for 50 m⁄s to 60 m⁄s over a 58 second interval.
Explanation:
A car traveling at 50 m⁄s to 60 m⁄s over a 58 second interval the displacement of car is found by using the formula:
[tex]s=\frac{1}{2}(v+u) t[/tex]
Where,
v is final velocity = 60 m/s
u is initial velocity = 50 m/s
t is time taken = 58 s
s is displacement
Now,
[tex]\Rightarrow s=\frac{1}{2}(60+50) 58[/tex]
[tex]\Rightarrow s=\frac{1}{2}(110) 58[/tex]
[tex]\therefore s=3190 \ m[/tex]
Hence, a car travels 3190 m if velocity is accelerated uniformly for 50 m⁄s to 60 m⁄s over a 58 second interval.
