Answer:
(A) 12.222 ohm (B) 990 W
Explanation:
We have given the voltage of the heating element V = 110 V
The current in the heating element i = 9 A
(a) According to ohm's law V =iR
So [tex]110=9\times R[/tex]
[tex]R=\frac{110}{9}=12.222ohm[/tex]
(b) The power dissipated in the resistor is given by [tex]P=i^2R=9^2\times 12.222=990W[/tex]
So the power dissipated = 990 W
