Answer:
Option D. 0.568 s
Given:
Length of the rope, l = 10.4 m
mass of the rope, M = 2.31 kg
Tension, T = 74.4 N
Solution:
The velocity of the wave, [tex]v_{w}[/tex] is given as:
[tex]v_{w} = \sqrt(\frac{T}{\frac{M}{l}})[/tex]
Putting the values in the above formula:
[tex]v_{w} = \sqrt(\frac{74.4}{\frac{2.31}{10.4}})[/tex]
[tex]v_{w} = \sqrt 334.96 = 18.30 m/s[/tex]
Time taken, t can be calculated as:
[tex]t = \frac{distance}{speed or velocity}[/tex]
Since distance between two end is the length of the rope
Therefore, using the formula for time, t:
[tex]t = \frac{10.4}{18.30}[/tex]
t = 0.568 s
therefore, time taken for the disturbance to travel from one end to the other is t = 0.568 s
