Answer:
The exit temperature of hot water =200.005°F
Explanation:
Given that
Volume flow rate of water = 20 gpm ⇒
Volume flow rate of water =[tex]0.00126\frac{m^3}{s}[/tex]
inlet temperature of water = 200°F
Heating load = 92.000 Btu/hr ⇒ Heating load= 0.0269 KW
We know that mass flow rate is given as
[tex]\dot{m}=\rho Q[/tex]
So mass flow rate of water = 1000 x 0.00126 Kg/s
mass flow rate of water= 1.26 Kg/s
Now by balancing heat
Heating load = [tex]\dot{m}C_p\Delta T[/tex]
[tex]0.0269=1.26\times 4.178(T_o-200)[/tex]
[tex]T_o[/tex]=200.005°F
So the exit temperature of hot water =200.005°F
