Answer:
18.26 mA
Explanation:
We have given voltage V = 8.3 Volt
Resistance R=180 ohm
Inductance L=43 mH
Time at which we have to find the current t=0.120 ms
The current in the RL circuit is given by [tex]i=\frac{V}{R}(1-e^\frac{-t}{\tau })[/tex] here [tex]\tau[/tex] is time constant which is given by [tex]\tau =\frac{L}{R}=\frac{43\times 10^{-3}}{180}=0.238ms[/tex]
So the current [tex]i=\frac{V}{R}(1-e^\frac{-t}{\tau })=\frac{8.3}{180}(1-e^\frac{-0.120}{0.238})=18.26mA[/tex]
