Respuesta :

carlosego

For this case we have that the equation of a line of the slope-intersection form is given by:

[tex]y = mx + b[/tex]

Where:

m: It's the slope

b: It is the cut-off point with the y axis

In this case we have the following data:

[tex]m = - \frac {5} {3}\\(x, y) :( 2,0)[/tex]

Then, the equation is of the form:

[tex]y = - \frac {5} {3} x + b[/tex]

We find "b" replacing the point:

[tex]0 = - \frac {5} {3} (2) + b\\0 = - \frac {10} {3}\\b = \frac {10} {3}[/tex]

Thus, the equation is:

[tex]y = - \frac {5} {3} x + \frac {10} {3}[/tex]

Answer:

[tex]y = - \frac {5} {3} x + \frac {10} {3}[/tex]

luisejr77

Answer:

[tex]y=-\frac{5}{3}x+\frac{10}{3}[/tex]

Step-by-step explanation:

The equation of a line has the following form:

[tex]y=mx+b[/tex]

Where m is the slope of the line and b is the intercept with the y axis.

In this case we know that:

[tex]m=-\frac{5}{3}[/tex]

So the equation is:

[tex]y=-\frac{5}{3}x+b[/tex]

To find b we substitute the point in the equation and solve for b

[tex]0=-\frac{5}{3}(2)+b[/tex]

[tex]b=\frac{10}{3}[/tex]

Then the equation of the line in the form of pending interception is:

[tex]y=-\frac{5}{3}x+\frac{10}{3}[/tex]

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