Respuesta :

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Answer:

[tex]\angle 1\ \leftrightarrow\ \angle 2\\\\\angle3\ \leftrightarrow\ \angle 4\\\\\angle U\ \leftrightarrow\ \angle S[/tex]

Step-by-step explanation:

[tex]\text{If}\ AB\cong AC,\ BD\cong CD,\ RSTU\ \text{is a parallelogram (rectangle)},\ \text{then}\\\\\angle 1\ \leftrightarrow\ \angle2\\\angle3\ \leftrightarrow\ \angle4\\\angle C\leftrightarrow\ \angle B\\\angle 5\ \leftrightarrow\ \angle6\\\angle7\ \leftrightarrow\ \angle 8\\\angle R\ \leftrightarrow\ \angle T\\\angle S\ \leftrightarrow\ \angle U[/tex]

Answer:

21). Option A

22). Option C

23). Option B

Step-by-step explanation:

In figure number 21,

Given figure is of a kite. As per property of a kite diagonals of the kite bisect each other at 90° and diagonals bisect the congruent angles.

Therefore, in the given kite ∠A and ∠D are the congruent angles and diagonal AD bisects these angles.

∠1 ↔ ∠2

Option A. is the answer.

In the figure 22,

As we have discussed ∠A and ∠D are congruent angles and side AD bisects these angles.

Therefore, ∠3 ↔ ∠4

Option C. is the answer.

In the figure 23,

In this figure RSTU is a rectangle and every angle of a rectangle measure 90°.

Therefore, ∠S ≅ ∠U ≅ 90°

Option B. is the answer.

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