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A cliff diver on an alien planet dives off of a 32 meter tall cliff and lands in a sea of hydrochloric acid 1.20 seconds later. Assuming that the extra-terrestrial’s initial speed was zero, what is the free fall acceleration of this strange world?

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thedemon840

Answer:

44.4m/s^2

Explanation:

Use the formula...S = ut + 1/2at^2

where...S = 32m...u = 0m/s....t = 1.20s

32 = (0)(1.20) + 0.5(1.20^2)a

;Acceleration of free fall = 44.4m/s^2

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