Answer:
88
Step-by-step explanation:
Lets call L the number if lecturers and P the professors. As all of them together sum 136:
P + L = 136
Then, as for every 11 lecturers they have 6 professors, we know that:
6 P = 11 L
If we divide both sides of this equation by 6:
6P / 6 = 11L / 6
P = (11/6)L
So we have the equivalence of 1 Professor in Lecturers. If we replace this equation on our first equation:
P + L = 136
(11/6) L + L = 136 or what is the same:
(11/6) L + (6/6) L = 136
(11+6)/6 L = 136
17/6 L = 136
If we multiply both sides by 6/17
(17/6) L * (6/17) = 136 * 6/17
L = 48
So, we replace the number of lecturers to find P:
P + L = 136
P = 136 - L
P = 136 - 48
P = 88
The college employs 88 professors
