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The combustion of propane (C3H8) in the presence of excess oxygen yields CO2 and H20: C3H8 (8) + 5O2 (g) - 3CO2 (s) + 4H20 (8) When 2.5 mol of O2 are consumed in their reaction, A) 3.0 B) 7.5 C) 1.5 mol of CO2 are produced. D) 4.2 E) 2.5

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danidg02

Answer:

c) 1.5 mol

Explanation:

Using the mole ratio perform the operation:

[tex]2.5 \times \frac{3}{5} [/tex]

=1.5 mol

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