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What is the velocity of a beam of electrons that go undeflected when passing through crossed electric and magnetic fields of magnitude 1.4x10^4 V/m and 2.93x10^-3 T, respectively?

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ch3ng27

Answer:

[tex]v = 4.78 \times {10}^{6} m {s}^{ - 1} [/tex]

Explanation:

Since the electrons are undeflected,

Magnetic force = Electric force

evB = eE

v = E/B

[tex]v = \frac{1.4 \times {10}^{4} }{2.93 \times {10}^{ - 3} } \\ = 4.78 \times {10}^{6} m {s}^{ - 1} [/tex]

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