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An object of mass m is sliding with speed vi at some instant across a level tabletop, with which its coefficient of kinetic friction is µ. It then moves through a distance d and comes to rest. Which of the following equations for the speed vi is reasonable?vi = v2µdvi = v2µmgdvi = v-2µmgdvi = v-2µgdvi = v2µgd

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Answer:

√2µgd = vi

Explanation:

Given that the mass of object is m

Sliding speed of object is vi

coefficient of kinetic friction is µ

Distance covered is d

Final speed, vf is 0

Equation to apply will be;

v²f=v²i-2µgd where  g is acceleration due to gravity

v²f+2µgd=v²i----------------------but v²f = 0

2µgd=v²i

√2µgd = vi

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