Answer:
90
Step-by-step explanation:
Using inequalities we can understand this problem.
First call X the number of products in the original batch
Then X/6 is the number of muffins in each tray before putting the croissants
Finally, X/6+5 are the products in each tray counting the croissants, and this quantity at least should be 20, it means:
[tex]\frac{X}{6}+5\geq 20[/tex]
Isolating X:
[tex]\frac{X}{6}\geq 20-5\\\frac{X}{6}\geq 15\\X\geq 6*15\\X\geq 90[/tex]
The least possible number of muffins in the baker's original batch is 90.
