If the two wires make the same angle with the vertical, what must this angle be if the tension in each wire is equal to 0.75 of the weight of the frame? (Neglect any friction between the wall and the picture frame).

Respuesta :

Answer:

The angle is 48.24°.

Explanation:

Given that,

Tension [tex]T= 0.75 \times W[/tex]

Let [tex]\theta[/tex] be the angle of wires with vertical

The total force in vertical direction from the wires

[tex]F= 2T\cos\theta[/tex]

We need to calculate the angle

Using balance equation

[tex] 2T\cos\theta=W[/tex]

Put the value of T in the equation

[tex]2\times 0.75 \times W\cos\theta=W[/tex]

[tex]\cos\theta=\dfrac{1}{2\times0.75}[/tex]

[tex]\cos\theta=0.666[/tex]

[tex]\theta=\cos^{-1}0.666[/tex]

[tex]\theta=48.24^{\circ}[/tex]

Hence, The angle is 48.24°.