Answer:[tex]h=160.84 W/m^2-K[/tex]
Explanation:
Given
mass flow rate=0.3 kg/s
diameter of pipe=5 cm
length of pipe=10 m
Inside temperature=22
Pipe surface =100
Temperature drop=30
specific heat of vapor(c)=2190 J/kg.k
heat supplied [tex]Q=mc\Delta T=0.3\times 2190\times (30)[/tex]
Heat due to convection =hA(100-30)
[tex]A=\pi d\cdot L[/tex]
[tex]A=\pi 0.05\times 10=1.571 m^2[/tex]
[tex]Q_{convection}=h\times 1.571\times (100-22)=122.538 h[/tex]
[tex]Q=Q_{convection}[/tex]
19,710=122.538 h
[tex]h=160.84 W/m^2-K[/tex]