PLEASE HELP!!!!! ME AND MY MATH CREW ARE TRYING TO FIGURE OUT THIS PROBLEM!!!! IT'S A EMERGENCY!!!!!!

Given: Line segment AB,

with point A at (4, 3) and point B at (10, –9).

Point C lies on segment AB,

such that the ratio of AC:CB is 3:1.

Find the coordinates of point C.

Question 8 options:

(7, –3)


(8.5, –6)


(5.5, 0)


(8, –5)


(9, –7)

Respuesta :

Answer:

a

Step-by-step explanation:

Answer:

The coordinates of the point C are:

                          (8.5,-6)

Step-by-step explanation:

We know that if a point C(x,y) divides the line segment A(a,b) B(c,d) in the ratio m:n then the coordinates of point C are given by:

[tex]x=\dfrac{m\times c+n\times x}{m+n}\ ,\ y=\dfrac{m\times d+n\times b}{m+n}[/tex]

Here we have:

m=3 and n=1

a=4 , b=3 , c=10 and d= -9

Hence, we have:

[tex]x=\dfrac{3\times 10+1\times 4}{3+1}\ ,\ y=\dfrac{3\times (-9)+1\times 3}{3+1}\\\\x=\dfrac{30+4}{4}\ ,\ y=\dfrac{-27+3}{4}\\\\x=\dfrac{34}{4}\ ,\ y=\dfrac{-24}{4}\\\\x=8.5\ ,\ y=-6[/tex]

Hence, the coordinates of the point C are:

                      (8.5,-6)