given line passes through the points (-4, -3) and( 4, 1) what is the equation in point slope form of the line that's perpendicular to the given line and passes through the point (-4,3)

Respuesta :

Answer:

y= -2x-5

Step-by-step explanation:

First find the gradient of the first line

[tex]m = \frac{y2 - y1}{x2 - x1} [/tex]

m=

[tex] \frac{1 - - 3}{4 - - 4} [/tex]

m=

[tex] \frac{4}{8} [/tex]

m=1/2

From this we can find the gradient of the perpendicular line, or the normal.

m1 × m2 = -1

Replace m1 with 1/2

1/2 × m2 = -1

m2= -2

Substitute values into

y-y1=m (x-x1)

y-3=-2 (x+4)

y-3=-2x -8

y=-2x-5

Answer:

y + 3= one- fourth (x +4

Step-by-step explanation: