an online seed supplier packages a seed mix that costs the company 20.70$ per pound the mix includes poppy seeds costing 24$ per pound and clover seeds costing 13.00$ per pound if a worker is going to prepare some of this mix and has already measured out 26 pounds of poppy seeds what quantity of clover seeds should be added?​

Respuesta :

Answer:

The quantity of clover seeds in pounds to be added is 11.14

Step-by-step explanation:

Let

x -----> the quantity of poppy seeds in pounds

y -----> the quantity of clover seeds in pounds

we know that

[tex]24(x)+13(y)=20.70(x+y)[/tex] -----> equation A

[tex]x=26\ pounds[/tex] ----> equation B

substitute equation B in equation A and solve for y

[tex]24(26)+13(y)=20.70(26+y)[/tex]

[tex]624+13y=538.2+20,70y[/tex]

[tex]20.70y-13y=624-538.2[/tex]

[tex]7.7y=85.8[/tex]

[tex]y=11.14\ pounds[/tex]

therefore

The quantity of clover seeds in pounds to be added is 11.14

Answer:

11.14 pounds ( approx )

Step-by-step explanation:

Let x pounds of poppy seeds and y pounds of clover seeds were mixed,

∵ Poppy seed costs 24$ per pound and clover seed costs 13.00$ per pound,

Thus the total cost of x pounds of poppy seeds and y pounds of clover seeds = 24x + 13y,

According to the question,

Resultant mixture costs $ 20.70 per pound,

∴ Total cost = 20.70(x+y),

[tex]\implies 24x + 13y = 20.70(x+y)[/tex]

[tex]24x + 13y = 20.70x + 20.70y[/tex]

[tex]24x - 20.70x = 20.70y - 13y[/tex]

[tex]3.3x = 7.7y[/tex]

[tex]\implies y = \frac{3.3}{7.7}x=\frac{3}{7}x[/tex]

If x = 26,

[tex]y=\frac{3}{7}\times 26=\frac{78}{7}=11.1428571429\approx 11.14[/tex]

Hence, 11.14 pounds of clover seeds should be added.