Answer:
[tex]\large \boxed{\text{2000 s}}[/tex]
Explanation:
1. Calculate the mass of methanol needed to fill the tank
[tex]\begin{array}{rcr}\text{Tank capacity} & = & \text{2274. kg}\\\text{Less mass present} & = & -\text{549. kg}\\\text{Remaining capacity} & = & \text{1725. kg}\\\end{array}[/tex]
2. Calculate the volume of methanol needed to fill the tank
ρ = 0.792 g/cm³ = 0.792 kg/L
[tex]V = \text{1725. kg} \times \dfrac{\text{1 L}}{\text{0.792 kg}} = \text{2178 L}[/tex]
3.Calculate the time required to fill the tank
[tex]\text{Time} = \text{2178 L} \times \dfrac{\text{1 s }}{\text{1.1 L}} = \text{2000 s}\\\\\text{It will take $\large \boxed{\textbf{2000 s}}$ (about 33 min) for the tank to overflow}[/tex]
Note: The answer can have only two significant figures because that is all you gave for the flow rate.
