Answer:
Final temperature is 302 K
Explanation:
You can now initial volume with ideal gas law, thus:
V = [tex]\frac{n.R.T}{P}[/tex]
Where:
n are moles: 2 moles
R is gas constant: 0,082 [tex]\frac{atm.L}{mol.K}[/tex]
T is temperature: 300 K
P is pressure: 1 atm
V is volume, with these values: 49,2 L
The work in the expansion of the gas, W, is: 1216 J - 34166 J = -32950 J
This work is:
W = P (Vf- Vi)
Where P is constant pressure, 1 atm
And Vf and Vi are final and initial volume in the expansion
-32950 J = -1 atm (Vf-49,2L) × [tex]\frac{101325 J}{1 atm.L}[/tex]
Solving: Vf = 49,52 L
Thus, final temperature could be obtained from ideal gas law, again:
T = [tex]\frac{P.V}{n.R}[/tex]
Where:
n are moles: 2 moles
R is gas constant: 0,082 [tex]\frac{atm.L}{mol.K}[/tex]
P is pressure: 1 atm
V is volume: 49,52 L
T is final temperature: 302 K
I hope it helps!
