[tex](4 \times {10}^{4} ) \times (2.2 \times {10}^{ - 6} )[/tex]
before you proceed to solve, change the 2.2 to standard form
which is
[tex]22 \times {10}^{ - 1} [/tex]
because in standard form, movement to the right gives a negative exponent of 10 depending on the number of moves you make.
and for 2.2 we move only once that is why we had negative exponent of 1
now the new equation is
[tex](4 \times {10}^{4} ) \times (22 \times {10}^{ - 1} \times {10}^{ - 6} )[/tex]
from the first law of indices, which states, if numbers of the same base multiply each other, take only one of the base and add the exponent,
so now the equation is
[tex](4 \times {10}^{4} ) \times (22 \times {10}^{ - 1 - 6} )[/tex]
[tex] = (4 \times {10}^{4} ) \times (22 \times {10}^{ - 7} )[/tex]
now multiplying the bracket
[tex](4 \times 22) \times ( {10}^{4 - 7} )[/tex]
[tex] = 88 \times {10}^{ - 3} [/ 88 is not in standard form , we need to change it to standard form
thus
[tex]8.8 \times {10}^{1} [/tex]
so now the whole equation becomes
[tex] 8.8\times {10}^{1 - 3} [/tex]
[tex] 8.8\times {10}^{ - 2} [/tex]
as final answer
