Answer:
Part a) The coordinates of the suspect's car at its final destination are (4,4)
Part b) The distance traveled by the suspect was 10 miles
Part c) [tex]d=5.66\ mi[/tex]
Step-by-step explanation:
The correct question in the attached figure
Part a) What are the coordinates of the suspect's car at its final destination?
we know that
The original position is the origin of a Cartesian coordinate system (0,0)
1) The suspect's car was tracked going 5 mi due east
That means----> 5 mi at right
the new coordinates are (5,0)
2) The suspect's car was tracked going 4 mi due north
That means----> 4 mi up
the new coordinates are (5,4)
3) The suspect's car was tracked going 1 mi due west
That means----> 1 mi at left
the new coordinates are (4,4)
therefore
The coordinates of the suspect's car at its final destination are (4,4)
Part b) What was the distance traveled by the suspect?
The distance traveled is
5 mi due east + 4 mi due north + 1 mi due west
[tex]5+4+1=10\ mi[/tex]
therefore
The distance traveled by the suspect was 10 miles
Part c) What is the distance as the crow flies between the original position and the final position of the suspect's car?
the formula to calculate the distance between two points is equal to
[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]
Remember that
The original position was (0,0) and the final position was (4,4)
substitute in the formula
[tex]d=\sqrt{(4-0)^{2}+(4-0)^{2}}[/tex]
[tex]d=\sqrt{(4)^{2}+(4)^{2}}[/tex]
[tex]d=\sqrt{32}\ mi[/tex]
[tex]d=5.66\ mi[/tex]
