Respuesta :
Answer:
Step-by-step explanation:
Steps:
1. Let x = #
2. "Five less than six times a number" can be written as: 6x - 5
3. "is at least" is the same as "greater than or equal to" and can be written as: >=
4. "nine subtracted from two times that number" can be written as: 2x - 9
5. the equation is: 6x - 5 >= 2x - 9
6. solve for x by grouping the x variable terms on one side and the constants on the other side:
6x - 5 >= 2x - 9
-2x +5 -2X +5
4x >= -4
7. divide each side by 4, and you get: x = -1
The solution according to the given statement is "x = -1".
According to the question,
The equation will be:
- [tex]6x - 5 \geq 2x - 9[/tex]
By adding "5" both sides, we get
→ [tex]6x - 5+5 \geq 2x - 9+5[/tex]
→ [tex]6x \geq 2x-4[/tex]
By subtracting "2x" form both sides, we get
→ [tex]6x-2x \geq 2x-4-2x[/tex]
→ [tex]4x \geq -4[/tex]
→ [tex]x \geq -\frac{4}{4}[/tex]
→ [tex]x = -1[/tex]
Thus the above answer is appropriate.
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