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22-05-2016
Chemistry

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how many grams of ca(po4)2 would be produced when 1.5 grams of (nh4)3po4 is reacted with an excess of ca(oh)2

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Willchemistry Willchemistry

22-05-2016

Molar mass :

(NH₄)₃PO₄ = 149.0 g/mol

Ca₃(PO₄)₂ = 310.17 g/mol

2 (NH₄)₃PO4 + 3 Ca(OH)₂= Ca₃(PO₄)₂ + 6 NH₄OH

2 * 149 g --------- 310.17 g
1.5 g -------------- ?

mass = 1.5 * 310.17 / 2 * 149

mass = 465.255 / 298

= 1.561 g of Ca₃(PO₄)₂

hope this helps!

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