A blue-light photon has a wavelength of 4.80 × 10-7 meter. What is the energy of the photon?

The energy of a photon is presented in the equation of E = hc/gamma where E is the energy of the photon, hc is 1.99x10^-25 joules – meter and gamma is the wavelength of the photon. Since you are given a blue-light photon with a wavelength of 4.80 × 10-7 meter, plug in the values to the energy equation and you will get 4.15x10^-19 joules.

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aristocles aristocles · Answer 2 · 2019-05-28T03:52:09+02:00

Answer:

[tex]Energy = 4.125 \times 10^{-19} J[/tex]

[tex]Energy = 2.6 eV[/tex]

Explanation:

As we know that energy associated with a photon is given by

[tex]Energy = \frac{hc}{\lambda}[/tex]

here we know that

[tex]h = 6.6 \times 10^{-34}[/tex]

c = speed of light

now we have

[tex]\lambda = 4.80 \times 10^{-7} m[/tex]

now we will have

[tex]E = \frac{(6.6 \times 10^{-34})(3 \times 10^8)}{4.80 \times 10^{-7}}[/tex]

[tex]E = 4.125 \times 10^{-19} J[/tex]

now we can also convert it into electron volt

[tex]E = \frac{4.125 \times 10^{-19}}{1.6 \times 10^{-19}} = 2.6 eV[/tex]