Respuesta :
Volume = 50.0 mL in liters : 50.0 / 1000 = 0.05 L
n = M x V
n = 0.20 x 0.05
n = 0.01 moles of solute
n = M x V
n = 0.20 x 0.05
n = 0.01 moles of solute
The moles of potassium nitrate present in the 50 ml of 0.2M solution has been 4 moles.
Molarity can be defined as the moles of solute in a litre of solution. The solution of potassium nitrate has been prepared to be of Molarity 0.2 M. The moles of solute present in the solution can be calculated as:
Molarity = moles [tex]\times[/tex] volume (L)
The given volume = 50 ml
1000 ml = 1 L
50 ml = 0.05 L
Molarity of the solution = 0.2 M
The moles of solute:
0.2 = moles [tex]\times[/tex] 0.05
Moles of Potassium nitrate = 4
The moles of potassium nitrate present in the 50 ml of 0.2M solution has been 4 moles.
For more information about the moles of solute, refer to the link:
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