A 10,000-kg railroad car travels down the track at 30 m/s and hits a second stationary railroad car of 20,000 kg. The cars become coupled and continue traveling. Calculate the final velocity of the cars.

Respuesta :

Answer:

10 m/s

Explanation:

The problem can be solved by using the law of conservation of momentum: the initial momentum has to be equal to the final momentum, so we can write the following

[tex]p_i = p_f[/tex]

[tex]m_1 u_1 + m_2 u_2 = (m_1 +m_2 )v[/tex]

where

[tex]m_1 = 10,000 kg[/tex] is the mass of the first car

[tex]u_1=30 m/s[/tex] is the initial velocity of the first car

[tex]m_2 = 20,000 kg[/tex] is the mass of the second car

[tex]u_2 = 0[/tex] is the initial velocity of the second car

[tex]v[/tex] is the final velocity of the two combined cars after the collision

Re-arranging the equation and substituting the numbers, we find

[tex]v=\frac{m_1 u_1 +m_2 u_2}{m_1+m_2}=\frac{(10,000)(30)-0}{10,000+20,000}=10 m/s[/tex]