Monteinat7ra Monteinat7ra

24-05-2016
Chemistry

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a gas at 155 kPa and 298 K occupies a container with an initial volume of 1.00 L. By changing the volume, the pressure of the gas increases to 605 kPa as the temperature is raised to 398 K. What is the new volume?

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taskmasters taskmasters

24-05-2016

Given: P1=155kPa P2=605kPa T1=298K T2=398K V1=1.00L

Unknown: V2=?

Formula: V2= V1P1T2/P2T1

Solution: V2= 1.00Lx155kPax398K/605kPax298K
V2= 61,690/180,290=n
Answer: V2= 0.34L is the new volume

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