Respuesta :
[tex]R_{sphere}= \frac{1}{2} *16=8[mm]\\
A_{sphere}=4 \pi R^{2}\\
A_{cylinder}=2 \pi R(R+h)\\\\
4\pi R^{2}=2 \pi R(r+h)\\
\frac{4\pi R^{2}}{2 \pi R} =r+h\\
h= \frac{4\pi R^{2}}{2 \pi R}-R=2R-R=R\\
R=8[mm][/tex]
So the answer is B. 8 mm
So the answer is B. 8 mm